Concepts

An Explanation of Chi-Squared Distributions

Yate's Correction Term

X2 Tests Part I

X2 Tests Part II

X2 Tests Part III

X2 Tests Part IV

Homogeneity X2
Part I

X2 Contingency Testing

Contingency X2

Homogeneity
X2 - A

Homogeneity X2
Part II

The Calculation
of X2

Homework Assignment #2 Questions

Homework Assignment #2 Answers

Yate's Correction Term

Yate’s correction term - When n is 50 or less and there are only two classes, Yate’s correction term is used to improve the accuracy of the X test. The binomial distribution is used for an exact test of discrete classes. The X test is an approximate test used when class sizes are large. Yate’s correction is used for small class sizes such that the X test more closely approximates the true significance level found from the binomial distribution.

Example 1

Strickberger, M.W. 1968. Genetics. The Macmillan Co., New genotYork. pg. 132.

With 1df Ho:3:1 ratio, n = 50

observed - 30 tall plants : 20 short plants
expected - 37.5 tall : 12.5 short

X = [| observed - expected |- 1/2]
X = [l obseexpected number

The Yate’s correction term is to subtract 1/2 from the absolute value of observed number minus expected.

Example 2

  Tall Short Totals
observed 30 20 50
expected 37.5 12.5 50
observed-expected -7.5 +7.5  
|observed-expected| 7.5 7.5  
|observed-expected -1/2| 49.0 49.0  

(| observed - expected |- 1/2)
(| observedexpected

49.0 = 1.31         49.0 = 3.92
37.5                  12.5

X = 1.31 + 3.92 = 5.23

The critical X value for 1df, a = 0.05 is 3.84. 5.23 is too large, because it is larger than 3.84.

Reject Ho:3:1 ratio because calculated X2 is too large.
(Tt x Tt mating rejected)

Now test Ho:1:1 ratio.

  Tall Short Totals
observed 30 20 50
expected 25=1/2(50) 25=1/2(50) 50
observed-expected 5 -5  
|observed-expected| -1/2 5-1/2=4.5 5-1/2=4.5  
|observed-expected| -1/2 20.25 20.25  

{| observed - expected | - 1/2}2 20.25 = .81 20.25 = .81
expected number 25 25

X = 0.81 + 0.81, a = 0.05, df = 1.
X = 1.62

1.62 is the calculated X which is less than the critical
X2 = 3.84, so fail to reject Ho. The evidence supports
a 1:1 ratio of a Tt x tt mating.

** A hypothesis can never be proven, but the observed data may result in a failure to reject the null hypothesis.

Copyright 2000©, Ted Helms

Back | Home | Top | Next
Home Forward Back