Concepts

An Explanation of Chi-Squared Distributions

Yate's Correction Term

X2 Tests Part I

X2 Tests Part II

X2 Tests Part III

X2 Tests Part IV

Homogeneity X2
Part I

X2 Contingency Testing

Contingency X2

Homogeneity
X2 - A

Homogeneity X2
Part II

The Calculation
of X2

Homework Assignment #2 Questions

Homework Assignment #2 Answers

X2 Tests Part I

X2 Test With More Than 1 df

X2 test is calculated without Yate's correction term.

Di-hybrid F cross AaBb results in four possible classes, assuming complete dominance gene action at both loci.

  A_B_ A_bb aaB_ aabb Totals
observed 1080 210 200 110 1600
expected  9  (1600)
16
         =900
 3  (1600)
16
        =300
 3  (1600)
16
        =300
 1 (1600)
16
       =100
 
observed-expected +180 -90 -100 +10  
(observed-expected)
          expected
36.00 27.00 33.33 1.0  

X = 36.00 + 27.00 +33.33 + 1.0 = 97.33

4 classes - 1df = 3df. If we know the total number of individuals, then three classes are variable and the fourth class number is fixed.

Critical X with 3df, a = 0.05 = 7.82. The calculated X = 97.33 is larger than would be expected to occur in 95% of repeated experiments, reject Ho.

Copyright 2000©, Ted Helms

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