Concepts

An Explanation of Chi-Squared Distributions

Yate's Correction Term

X2 Tests Part I

X2 Tests Part II

X2 Tests Part III

X2 Tests Part IV

Homogeneity X2
Part I

X2 Contingency Testing

Contingency X2

Homogeneity
X2 - A

Homogeneity X2
Part II

The Calculation
of X2

Homework Assignment #2 Questions

Homework Assignment #2 Answers

X Tests Part III

Contingency X Test With Yates Correction

X = (| ad-bc| - 1/2N) N
       (a+b)(a+c)(c+d)(b+d)

X = (|2000 - 2700| - 112.5) x 225
              (110)(170)(115)(55)

X = (700 - 112.5) x 225
           1,182,275,000

X = 0.66 with 1df; critical X = 3.84 for 1df, a = 0.05

Because the calculated X is less than the tabulated X, then accept Ho: no interaction between factors.

Another way to calculate Contingency X.

Observed:

Environment Dominant Recessive Totals
1998 80 30 110
1997 90 25 115
  170 55 225

Expected: Use P(A) P(B) = P(A and B) when A and B are independent.

Environment Dominant Recessive Relative Frequency
1998 110 x 170 x 225
(225)
110 x 55 x 225
(225)
110
225
1997 115 x 170 x 225
(225)
55 x 115 x 225
(225)
115
225
  170
225
 55 
225
225

 

  Dominant Recessive
1998 83.17 26.85
1997 86.92 28.05

Copyright 2000©, Ted Helms

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