Linkage Studies - Part I
| Source
of Data |
Amount
of Information per individual(i) |
|
| Repulsion:
testcross |
1
p(1-p) |
| |
|
| F2 |
2(1+2+p2)
(1-p2)(2+p2) |
|
For coupling data we use the same formulas, but substitute
1- p for p.
I = 1/Vp = ni
Example A:
Let p = 0.4, evaluate the amount of information for testcross vs F
data with repulsion linkage. Let n = 1000.
Testcross I = ni; i = 1/[p(1 - p)] = 1/(0.4 x 0.6) =
4.167
I = 1000(4.167) = 4167
The results show that 1455/4167 = 0.35 which means that in this example
F2 repulsion data only provides 35% as much information
as testcross data.
