F
Data
| Over
All |
df |
Probability |
Decision |
X 
= 25.095 |
3 |
very
small |
reject |
X
= 0.372 |
1 |
0.5-0.7 |
accept |
X
= 0.777 |
1 |
0.3-0.5 |
accept |
X
= 23.946 |
1 |
very
small |
reject |
The overall conclusion is that sums over all three F
families do not fit a 9:3:3:1 ratio. The A and B loci do segregate 3:1
ratio. There is a lack of independent assortment for the A and B loci,
or evidence of linkage.
The process of testing for a 9:3:3:1 ratio is repeated for each individual
F
family. Also, the X,
X,
X
are tested for each family.
| Family |
X |
X |
X |
df |
| 1 |
0.111 |
0.218 |
7.468 |
1 |
| 2 |
0.573 |
0.573 |
7.895 |
1 |
| 3 |
0.267 |
0.083 |
8.714 |
1 |
| Totals |
0.951 |
0.874 |
24.077 |
3 |
| Overall |
0.372 |
0.777 |
23.946 |
1 |
| Heterogenity |
0.579 |
0.097 |
0.131 |
2 |
Conclude that locus A and B segregate 3:1 and this ratio is homogeneous
for each locus. There is linkage between the A and B loci and the three
families are homogeneous for lack of independent assortment between
the two loci.
