Independent Assortment Of Two Genes
AaBb x AaBb:
| |
|
ĽAB |
ĽAb |
ĽaB |
Ľab |
| ĽAB |
|
AABB(1/16) |
ABAb(1/16) |
ABaB(1/16) |
ABab(1/16) |
| ĽAb |
AbAB(1/16) |
AbAb(1/16) |
AbaB(1/16) |
Abab(1/16) |
| ĽaB |
aBAB(1/16) |
aBAb(1/16) |
aBaB(1/16) |
aBab(1/16) |
| Ľab |
abAB(1/16) |
abAb(1/16) |
abaB(1/16) |
abab(1/16) |
If two events are independent, the joint probability of both events
is obtained by multiplying the probability of each separate event.
P(A) = P(a) = ˝ = P(B) = P(b)
P(AB) = P(A) X P(B) = ˝ x ˝ = Ľ
P(AB) = P(Ab) = P(aB) = P(ab)
P(AB) = P(Ab) = P(aB) = P(ab) = Ľ
P(AB + Ab +aB + ab)2 
1/16 probability for each event
