|
|
Homework Assignment #8
Answers
- a) P(2/R) = P(2 and
R) = (1/260)
= 1
P(R)
R) = (1/260)
= 10
b) The sample space has been reduced to ten
b) cars instead of 260
cars.
- The sample space is reduced when heterozygous and
homozygous recessive marker genotypes can be discarded.
Selecting only MM genotypes increases the probability
of identifying QQ genotypes due to coupling linkage
between M and Q.
- As recombination between the marker and QTL increases,
the conditional probability of Q given M decreases.
Fewer individuals that have a given marker genotype
will have the favorable QTL genotype as recombination
increases.
- If marker means are held constant, the recombination
fraction can be varied, which changes the means of
each QTL class. This is because there are three independent
equations, one for each marker class, and four unknown
parameters which include u1, u2,
u3, and r.
Copyright
2000©, Ted Helms
|
|