Percent Recombinant Genotypes versus Map Distance

Haldane's Mapping Function

Example I

Summarizing

Example II

Expected Frequency Example I

Expected Frequency Example II

Poisson Distribution

An Example

Kosambi's Map Function

Summary Of Map Distance Versus Observed Recombination Fraction

Homework Assignment #7 Questions

Homework Assignment #7 Answers

Haldane's Mapping Function

r = actual recombination; d = observed recombination.

A mapping function adjusts the proportion of observed recombinant genotypes to better estimate the map distance by counting single crossover events once and double crossover events twice to improve the estimate of the distance between loci. Haldane's mapping function assumes that crossover interference is zero.

The number of double crossovers is distributed as a Poisson variable. Let l equal the number of crossover events and
l = 2m. Where m is the map distance. For loci located less than 10 Centimorgans apart m=p. For loci located more than 10 Centimorgans apart, m does not equal p and m must be estimated using a mapping function. The mapping function considers the probability of double crossover events which causes m to be greater than p.

Distribution of the number of events Probability of that number of events
0 e-2m
1 me-2m
2 (m2/2)(e-2m)
3 (m3/6)(e-2m)

If e-2m is the probability of zero crossover events, then 1 - e-2m is the probability of at least one crossover event. The proportion of observed recombinant genotypes is (1/2)(1 - e-2m) because for each crossover event only one-half of the progeny will be recombinant types since only two of four strands participate in a crossover. Therefore there is a coefficient of 1/2 in front of the (1 - e-2m) term. The exponent of -2m is explained by the fact that is the probability of a crossover = 2m.

p = (1/2)(1 - e-2m) and this can be solved for m.

Determining the map distance using Haldane's mapping function is based on the observed proportion of recombinant genotypes adjusted for the number of unobservable double crossovers. Solving for m:

m = -(1/2) ln(1 -2p) and this equation converts the observed

recombination fraction (p) to Haldane's map distance (m). Haldane's mapping function estimates the map distance for at least one crossover (or more) between two loci. If the map distance is estimated based on the observed proportion of recombinant genotypes (without using the mapping function), then we are erroneously assumming that no double crossover events have occurred.

Liu, B.H. 1997. Statistical Genomics: Linkage Mapping and QTL Analysis. CRC Press. pg 18-19. pgs 328-328

Haldane, J.B.S. 1919. J. Genet. 8:299-309.

For short chromosome segments map distance = recombination fraction d = r "i.e. 4% recombination"
= 4cM = 8% crossover.

i.e. 4% recombination = 4cM = 8% c.o. events

However, consider three loci each separated by more than 10cm.

r does not equal r + r; r = r + r - 2r r.
r does not equal 40cM; r = 0.2 + 0.2 - 2(0.04) = 0.32.

Compare this to three loci closely liked.

The combination is additive for short distance.

r = r + r = 0.06 + 0.08 = 0.14 = 14%

2m = prob. of single crossover event between A and B loci
2n = prob. of single crossover event between B and C loci

2(m-mn) = probability of single crossover between A and B, excluding double crossovers between the A and B locus with B and C locus.

2(m-mn+mn) = 2m = probability of crossover between the A and B loci when 2-strand double crossover events are added to the single-crossover events.

2(n-mn+mn) = 2n = probability of crossover between B and C loci when both 2-strand double crossovers and single crossover are considered.

Copyright 2000©, Ted Helms

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