Percent Recombinant Genotypes versus Map Distance

Haldane's Mapping Function

Example I

Summarizing

Example II

Expected Frequency Example I

Expected Frequency Example II

Poisson Distribution

An Example

Kosambi's Map Function

Summary Of Map Distance Versus Observed Recombination Fraction

Homework Assignment #7 Questions

Homework Assignment #7 Answers

Summarizing

r = r + r - 2r r
    = 0.2+0.2+2(0.2)(0.2)
    = 0.32

where

r = 0.16 + 0.04 = 0.2
r = 0.16 + 0.04 = 0.2
r = 0.32

If recombination fractions were additive, then r should
= r + r.

You can see from the above analysis that Haldane only considered 2-strand double crossovers. He did not consider 3-strand and 4-strand double crossover.

The physical distance between loci does not equal the observed recombination fraction due to double crossovers which result in unobservable recombination.

Haldane showed that when the coefficient of coincidence equals one, then the map distance = m = -1/2ln (1-2r) where r is the observed recombination fraction.

Copyright 2000©, Ted Helms

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