Another Example
We want to determine the family size required to distinguish
a 3:1 ratio from a 9:7 ratio.
n = family size
| H(a)
3:1 = a2:a12 |
H(b)
9:7 = b2:b1 |
| Q
= 1/4, 1-Q = 3/4 |
Q
= 7/16, 1-Q = 9/16 |
| Q
= a1 |
Q
= b1 |
Var
(a1) = a1a2
n
|
Var(b1)
= b1b2
n
|
a = 0.025 with a one tailed
test so t = 1.96
= 1.96(0.929)
= 9.711
0.1875
n is equal to (9.711)2 = 94.3~94 individuals.
This is the same result as before using the square root
of (l1l2).
