\documentclass[12pt]{amsart} \usepackage{amssymb} \usepackage{amsmath} \usepackage{amsthm} \usepackage[all]{xy} \voffset=-1in \hoffset=-1in \textheight=10in \textwidth=6in \begin{document} \author{} \title{Math 724\\Fall 2005\\Homework 1} \date{} \maketitle \thispagestyle{empty} \pagestyle{empty} \centerline{\it Due Monday September 5, 2005.} \centerline{} \noindent 1. Let $R$ be a commutative ring with identity and $\mathfrak{N}\subseteq R$ the set of nilpotent elements of $R$. \begin{itemize} \item[a)] (5 pt) Show that $\mathfrak{N}$ is an ideal. \item[b)] (5 pt) Show that \[ \mathfrak{N}=\bigcap_{\mathfrak{P}:\text{prime}}\mathfrak{P}. \] \item[c)] (5 pt) Generalize part b) and show that if $I\subseteq R$ is an ideal, then \[ \sqrt{I}=\bigcap_{\mathfrak{P}\supseteq I}\mathfrak{P}, \] \noindent where the intersection is taken over all prime ideals containing $I$. \end{itemize} \centerline{} \noindent 2. (5 pt) Let $R$ be a commutative ring with identity and $I,J\subseteq R$ ideals. We define $(I:J)=\{r\in R\vert rJ\subseteq I\}$. Show that $(I:J)$ is an ideal of $R$. \centerline{} \noindent 3. Let $R$ be a commutative ring with identity. \begin{itemize} \item[a)] (5 pt) Show that if $R$ contains a non-principal ideal, then $R$ contains an ideal, $I$, that is maximal with respect to being non-principal. \item[b)] (5 pt) Show that any ideal that is maximal with respect to being non-principal is prime. \item[c)] (5 pt) Show that if $R$ contains an ideal that is not finitely generated, then $R$ contains an ideal, $J$, that is maximal with respect to being not finitely generated. \item[d)] (5 pt) Show that any ideal that is maximal with respect to being not finitely generated is prime. \item[e)] (5 pt) Show that $R$ is a PID if and only if every prime ideal of $R$ is principal. \item[f)] (5 pt) Show that $R$ is Noetherian (every ideal is finitely generated) if and only if every prime ideal is finitely generated. \end{itemize} \centerline{} \noindent 4. (5 pt) Let $R$ be a integral domain. Show that the following conditions are equivalent. \begin{enumerate} \item Every $R-$module is projective. \item Every $R-$module is injective. \item Every $R-$module is free. \item $R$ is a field. \end{enumerate} {\it Note that 1)$\Longleftrightarrow$ 2) and does not require the assumption integral domain, can you give an example of a commutative ring with 1 such that every ideal is projective (and injective) but not every module is free?} \end{document}